5x+3/7x=8x/10x-2

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Solution for 5x+3/7x=8x/10x-2 equation: 



5x+3/7x=8x/10x-2

We move all terms to the left:

5x+3/7x-(8x/10x-2)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R





Domain of the equation: 10x-2)!=0

x∈R



We get rid of parentheses

5x+3/7x-8x/10x+2=0

We calculate fractions


(-56x^2)/70x^2+5x+30x/70x^2+2=0

We multiply all the terms by the denominator


(-56x^2)+5x*70x^2+30x+2*70x^2=0

We add all the numbers together, and all the variables

(-56x^2)+30x+5x*70x^2+2*70x^2=0

Wy multiply elements

(-56x^2)+350x^3+140x^2+30x=0

We get rid of parentheses

-56x^2+350x^3+140x^2+30x=0

We do not support expression: x^3

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