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5x+3x+2x/5x=5x
We move all terms to the left:
5x+3x+2x/5x-(5x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3x+2x/5x=0
We multiply all the terms by the denominator
3x*5x+2x=0
We add all the numbers together, and all the variables
2x+3x*5x=0
Wy multiply elements
15x^2+2x=0
a = 15; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·15·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*15}=\frac{-4}{30} =-2/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*15}=\frac{0}{30} =0 $
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