5x+3y=12;2x-5y=-20

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Solution for 5x+3y=12;2x-5y=-20 system of equations: 


  • /| 5*x+3*y-12 = 0| 2*x-(5*y)+20 = 0
  • We try to solve the equation: 5*x+3*y-12 = 0
  • 5*x+3*y-12 = 0 // - 5*x-12
  • 3*y = -(5*x-12) // : 3
  • y = (-(5*x-12))/3
  • y = (12-(5*x))/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*x-(5*((12-(5*x))/3))+20 = 0| y = (12-(5*x))/3
  • (-1*5*(12-5*x))/3+2*x+20 = 0
  • 31/3*x-20+20 = 0
  • 31/3*x = 0
  • 31/3*x = 0 // : 31/3
  • x = 0
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (12-(5*x))/3: 
  • y = (12-(0*5))/3
  • y = (0+12)/3
  • y = 12/3
  • y = 4
  • We get a system of equations:
  • /| y = 4| x = 0

 

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