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5x+4(2x+1)=5(x+1)
We move all terms to the left:
5x+4(2x+1)-(5(x+1))=0
We multiply parentheses
5x+8x-(5(x+1))+4=0
We calculate terms in parentheses: -(5(x+1)), so:We add all the numbers together, and all the variables
5(x+1)
We multiply parentheses
5x+5
Back to the equation:
-(5x+5)
13x-(5x+5)+4=0
We get rid of parentheses
13x-5x-5+4=0
We add all the numbers together, and all the variables
8x-1=0
We move all terms containing x to the left, all other terms to the right
8x=1
x=1/8
x=1/8
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