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5x+4(x-7)=4(2x+3)
We move all terms to the left:
5x+4(x-7)-(4(2x+3))=0
We multiply parentheses
5x+4x-(4(2x+3))-28=0
We calculate terms in parentheses: -(4(2x+3)), so:We add all the numbers together, and all the variables
4(2x+3)
We multiply parentheses
8x+12
Back to the equation:
-(8x+12)
9x-(8x+12)-28=0
We get rid of parentheses
9x-8x-12-28=0
We add all the numbers together, and all the variables
x-40=0
We move all terms containing x to the left, all other terms to the right
x=40
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