5x+4(x-8)+12=7-2(x+1)-5x

Solution for 5x+4(x-8)+12=7-2(x+1)-5x equation:

5x+4(x-8)+12=7-2(x+1)-5x

We move all terms to the left:

5x+4(x-8)+12-(7-2(x+1)-5x)=0

We multiply parentheses

5x+4x-(7-2(x+1)-5x)-32+12=0


We calculate terms in parentheses: -(7-2(x+1)-5x), so:

7-2(x+1)-5x

determiningTheFunctionDomain
-2(x+1)-5x+7

We add all the numbers together, and all the variables

-5x-2(x+1)+7

We multiply parentheses

-5x-2x-2+7

We add all the numbers together, and all the variables

-7x+5

Back to the equation:

-(-7x+5)


We add all the numbers together, and all the variables

9x-(-7x+5)-20=0

We get rid of parentheses

9x+7x-5-20=0

We add all the numbers together, and all the variables

16x-25=0

We move all terms containing x to the left, all other terms to the right

16x=25

x=25/16

x=1+9/16