5x+4-2x=-(x+8)x=

Solution for 5x+4-2x=-(x+8)x= equation:

5x+4-2x=-(x+8)x=

We move all terms to the left:

5x+4-2x-(-(x+8)x)=0

We add all the numbers together, and all the variables

3x-(-(x+8)x)+4=0


We calculate terms in parentheses: -(-(x+8)x), so:

-(x+8)x

We multiply parentheses

-x^2-8x

We add all the numbers together, and all the variables

-1x^2-8x

Back to the equation:

-(-1x^2-8x)


We get rid of parentheses

1x^2+8x+3x+4=0

We add all the numbers together, and all the variables

x^2+11x+4=0

a = 1; b = 11; c = +4;
Δ = b2-4ac
Δ = 112-4·1·4
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{105}}{2*1}=\frac{-11-\sqrt{105}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{105}}{2*1}=\frac{-11+\sqrt{105}}{2}
$