5x+4-6(x-4)=4(x-2+10)

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Solution for 5x+4-6(x-4)=4(x-2+10) equation: 



5x+4-6(x-4)=4(x-2+10)

We move all terms to the left:

5x+4-6(x-4)-(4(x-2+10))=0

We add all the numbers together, and all the variables

5x-6(x-4)-(4(x+8))+4=0

We multiply parentheses

5x-6x-(4(x+8))+24+4=0



We calculate terms in parentheses: -(4(x+8)), so:

4(x+8)

We multiply parentheses

4x+32

Back to the equation:

-(4x+32)



We add all the numbers together, and all the variables

-1x-(4x+32)+28=0

We get rid of parentheses

-1x-4x-32+28=0

We add all the numbers together, and all the variables

-5x-4=0

We move all terms containing x to the left, all other terms to the right

-5x=4

x=4/-5

x=-4/5

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