5x+4/7=2

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Solution for 5x+4/7=2 equation: 



5x+4/7=2

We move all terms to the left:

5x+4/7-(2)=0

determiningTheFunctionDomain
5x-2+4/7=0

We multiply all the terms by the denominator


5x*7+4-2*7=0

We add all the numbers together, and all the variables

5x*7-10=0

Wy multiply elements

35x-10=0

We move all terms containing x to the left, all other terms to the right

35x=10

x=10/35

x=2/7

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