5x+4/x-4

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Solution for 5x+4/x-4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5*x+4/x-4 = 0

5*x^1+4*x^-1-4*x^0 = 0

(5*x^2-4*x^1+4*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2-4*x^1+4*x^0) = 0

x^1

5*x^2-4*x+4 = 0

5*x^2-4*x+4 = 0

DELTA = (-4)^2-(4*4*5)

DELTA = -64

DELTA < 0

x in { } 

x belongs to the empty set

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