5x+4/x-4=4x-3/x-3

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Solution for 5x+4/x-4=4x-3/x-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5*x+4/x-4 = 4*x-(3/x)-3 // - 4*x-(3/x)-3

5*x-(4*x)+4/x+3/x-4+3 = 0

5*x-4*x+4/x+3/x-4+3 = 0

1*x^1+7*x^-1-1*x^0 = 0

(1*x^2-1*x^1+7*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-1*x^1+7*x^0) = 0

x^1

x^2-x+7 = 0

x^2-x+7 = 0

DELTA = (-1)^2-(1*4*7)

DELTA = -27

DELTA < 0

x in { } 

x belongs to the empty set

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