5x+40=2x-7+8(x+1)

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Solution for 5x+40=2x-7+8(x+1) equation: 



5x+40=2x-7+8(x+1)

We move all terms to the left:

5x+40-(2x-7+8(x+1))=0



We calculate terms in parentheses: -(2x-7+8(x+1)), so:

2x-7+8(x+1)

determiningTheFunctionDomain
2x+8(x+1)-7

We multiply parentheses

2x+8x+8-7

We add all the numbers together, and all the variables

10x+1

Back to the equation:

-(10x+1)



We get rid of parentheses

5x-10x-1+40=0

We add all the numbers together, and all the variables

-5x+39=0

We move all terms containing x to the left, all other terms to the right

-5x=-39

x=-39/-5

x=7+4/5

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