5x+48+7xc=12(x+4)

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Solution for 5x+48+7xc=12(x+4) equation:


Simplifying
5x + 48 + 7xc = 12(x + 4)

Reorder the terms:
48 + 7cx + 5x = 12(x + 4)

Reorder the terms:
48 + 7cx + 5x = 12(4 + x)
48 + 7cx + 5x = (4 * 12 + x * 12)
48 + 7cx + 5x = (48 + 12x)

Add '-48' to each side of the equation.
48 + 7cx + -48 + 5x = 48 + -48 + 12x

Reorder the terms:
48 + -48 + 7cx + 5x = 48 + -48 + 12x

Combine like terms: 48 + -48 = 0
0 + 7cx + 5x = 48 + -48 + 12x
7cx + 5x = 48 + -48 + 12x

Combine like terms: 48 + -48 = 0
7cx + 5x = 0 + 12x
7cx + 5x = 12x

Solving
7cx + 5x = 12x

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5x' to each side of the equation.
7cx + 5x + -5x = 12x + -5x

Combine like terms: 5x + -5x = 0
7cx + 0 = 12x + -5x
7cx = 12x + -5x

Combine like terms: 12x + -5x = 7x
7cx = 7x

Divide each side by '7x'.
c = 1

Simplifying
c = 1

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