5x+4y=33;4y-3=x

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2x+y=8
x+3y=14

Solution for 5x+4y=33;4y-3=x system of equations: 


  • /| 5*x+4*y-33 = 0| 4*y-x-3 = 0
  • We try to solve the equation: 5*x+4*y-33 = 0
  • 5*x+4*y-33 = 0 // - 5*x-33
  • 4*y = -(5*x-33) // : 4
  • y = (-(5*x-33))/4
  • y = (33-(5*x))/4
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 4*((33-(5*x))/4)-x-3 = 0| y = (33-(5*x))/4
  • (4*(33-5*x))/4-x-3 = 0
  • 33-6*x-3 = 0
  • 30-6*x = 0
  • 30-6*x = 0 // - 30
  • -6*x = -30 // : -6
  • x = -30/(-6)
  • x = 5
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (33-(5*x))/4: 
  • y = (33-(5*5))/4
  • y = (33-25)/4
  • y = 8/4
  • y = 2
  • We get a system of equations:
  • /| y = 2| x = 5

 

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