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5x+5/2x=x
We move all terms to the left:
5x+5/2x-(x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
4x+5/2x=0
We multiply all the terms by the denominator
4x*2x+5=0
Wy multiply elements
8x^2+5=0
a = 8; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·8·5
Δ = -160
Delta is less than zero, so there is no solution for the equation
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