5x+55((-7-x)/11)=-35

Solution for 5x+55((-7-x)/11)=-35 equation:

5x+55((-7-x)/11)=-35

We move all terms to the left:

5x+55((-7-x)/11)-(-35)=0

We add all the numbers together, and all the variables

5x+55((-1x-7)/11)-(-35)=0

We add all the numbers together, and all the variables

5x+55((-1x-7)/11)+35=0

We multiply all the terms by the denominator


5x*11)+55((-1x-7)+35*11)=0

We add all the numbers together, and all the variables

5x*11)+55((-1x-7)=0

Wy multiply elements

55x^2=0

a = 55; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·55·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{110}=0$