5x+56=(3x-6)(3x-6)

Solution for 5x+56=(3x-6)(3x-6) equation:

5x+56=(3x-6)(3x-6)

We move all terms to the left:

5x+56-((3x-6)(3x-6))=0

We multiply parentheses ..

-((+9x^2-18x-18x+36))+5x+56=0


We calculate terms in parentheses: -((+9x^2-18x-18x+36)), so:

(+9x^2-18x-18x+36)

We get rid of parentheses

9x^2-18x-18x+36

We add all the numbers together, and all the variables

9x^2-36x+36

Back to the equation:

-(9x^2-36x+36)


We add all the numbers together, and all the variables

5x-(9x^2-36x+36)+56=0

We get rid of parentheses

-9x^2+5x+36x-36+56=0

We add all the numbers together, and all the variables

-9x^2+41x+20=0

a = -9; b = 41; c = +20;
Δ = b2-4ac
Δ = 412-4·(-9)·20
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-49}{2*-9}=\frac{-90}{-18}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+49}{2*-9}=\frac{8}{-18}
=-4/9
$