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5x+5=3x(x-1)
We move all terms to the left:
5x+5-(3x(x-1))=0
We calculate terms in parentheses: -(3x(x-1)), so:We get rid of parentheses
3x(x-1)
We multiply parentheses
3x^2-3x
Back to the equation:
-(3x^2-3x)
-3x^2+5x+3x+5=0
We add all the numbers together, and all the variables
-3x^2+8x+5=0
a = -3; b = 8; c = +5;
Δ = b2-4ac
Δ = 82-4·(-3)·5
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{31}}{2*-3}=\frac{-8-2\sqrt{31}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{31}}{2*-3}=\frac{-8+2\sqrt{31}}{-6} $
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