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5x+6+4/5x-26=106
We move all terms to the left:
5x+6+4/5x-26-(106)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
5x+4/5x-126=0
We multiply all the terms by the denominator
5x*5x-126*5x+4=0
Wy multiply elements
25x^2-630x+4=0
a = 25; b = -630; c = +4;
Δ = b2-4ac
Δ = -6302-4·25·4
Δ = 396500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{396500}=\sqrt{100*3965}=\sqrt{100}*\sqrt{3965}=10\sqrt{3965}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-630)-10\sqrt{3965}}{2*25}=\frac{630-10\sqrt{3965}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-630)+10\sqrt{3965}}{2*25}=\frac{630+10\sqrt{3965}}{50} $
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