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5x+6/3-2=10
We move all terms to the left:
5x+6/3-2-(10)=0
determiningTheFunctionDomain 5x-2-10+6/3=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2
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