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5x+6=3/4x+5
We move all terms to the left:
5x+6-(3/4x+5)=0
Domain of the equation: 4x+5)!=0We get rid of parentheses
x∈R
5x-3/4x-5+6=0
We multiply all the terms by the denominator
5x*4x-5*4x+6*4x-3=0
Wy multiply elements
20x^2-20x+24x-3=0
We add all the numbers together, and all the variables
20x^2+4x-3=0
a = 20; b = 4; c = -3;
Δ = b2-4ac
Δ = 42-4·20·(-3)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-16}{2*20}=\frac{-20}{40} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+16}{2*20}=\frac{12}{40} =3/10 $
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