5x+7-2(x+5)=x-10+2(x-3)

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Solution for 5x+7-2(x+5)=x-10+2(x-3) equation: 



5x+7-2(x+5)=x-10+2(x-3)

We move all terms to the left:

5x+7-2(x+5)-(x-10+2(x-3))=0

We multiply parentheses

5x-2x-(x-10+2(x-3))-10+7=0



We calculate terms in parentheses: -(x-10+2(x-3)), so:

x-10+2(x-3)

determiningTheFunctionDomain
x+2(x-3)-10

We multiply parentheses

x+2x-6-10

We add all the numbers together, and all the variables

3x-16

Back to the equation:

-(3x-16)



We add all the numbers together, and all the variables

3x-(3x-16)-3=0

We get rid of parentheses

3x-3x+16-3=0

We add all the numbers together, and all the variables

13!=0

There is no solution for this equation

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