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5x+7=2/5x+30
We move all terms to the left:
5x+7-(2/5x+30)=0
Domain of the equation: 5x+30)!=0We get rid of parentheses
x∈R
5x-2/5x-30+7=0
We multiply all the terms by the denominator
5x*5x-30*5x+7*5x-2=0
Wy multiply elements
25x^2-150x+35x-2=0
We add all the numbers together, and all the variables
25x^2-115x-2=0
a = 25; b = -115; c = -2;
Δ = b2-4ac
Δ = -1152-4·25·(-2)
Δ = 13425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13425}=\sqrt{25*537}=\sqrt{25}*\sqrt{537}=5\sqrt{537}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-115)-5\sqrt{537}}{2*25}=\frac{115-5\sqrt{537}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-115)+5\sqrt{537}}{2*25}=\frac{115+5\sqrt{537}}{50} $
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