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5x+7x*2x=4x+5
We move all terms to the left:
5x+7x*2x-(4x+5)=0
Wy multiply elements
14x^2+5x-(4x+5)=0
We get rid of parentheses
14x^2+5x-4x-5=0
We add all the numbers together, and all the variables
14x^2+x-5=0
a = 14; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·14·(-5)
Δ = 281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{281}}{2*14}=\frac{-1-\sqrt{281}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{281}}{2*14}=\frac{-1+\sqrt{281}}{28} $
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