5x+8(20-x)=2(x-5)

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Solution for 5x+8(20-x)=2(x-5) equation: 



5x+8(20-x)=2(x-5)

We move all terms to the left:

5x+8(20-x)-(2(x-5))=0

We add all the numbers together, and all the variables

5x+8(-1x+20)-(2(x-5))=0

We multiply parentheses

5x-8x-(2(x-5))+160=0



We calculate terms in parentheses: -(2(x-5)), so:

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

-3x-(2x-10)+160=0

We get rid of parentheses

-3x-2x+10+160=0

We add all the numbers together, and all the variables

-5x+170=0

We move all terms containing x to the left, all other terms to the right

-5x=-170

x=-170/-5

x=+34

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