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5x+x+19=3(2x-4)
We move all terms to the left:
5x+x+19-(3(2x-4))=0
We add all the numbers together, and all the variables
6x-(3(2x-4))+19=0
We calculate terms in parentheses: -(3(2x-4)), so:We get rid of parentheses
3(2x-4)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
6x-6x+12+19=0
We add all the numbers together, and all the variables
31!=0
There is no solution for this equation
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