5x+x+2x+3x=2x-1+(3x*2)*2

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Solution for 5x+x+2x+3x=2x-1+(3x*2)*2 equation: 



5x+x+2x+3x=2x-1+(3x*2)*2

We move all terms to the left:

5x+x+2x+3x-(2x-1+(3x*2)*2)=0

We add all the numbers together, and all the variables

5x+x+2x+3x-(2x-1+(+3x*2)*2)=0

We add all the numbers together, and all the variables

11x-(2x-1+(+3x*2)*2)=0



We calculate terms in parentheses: -(2x-1+(+3x*2)*2), so:

2x-1+(+3x*2)*2

determiningTheFunctionDomain
2x+(+3x*2)*2-1

We multiply parentheses

2x+12x-1

We add all the numbers together, and all the variables

14x-1

Back to the equation:

-(14x-1)



We get rid of parentheses

11x-14x+1=0

We add all the numbers together, and all the variables

-3x+1=0

We move all terms containing x to the left, all other terms to the right

-3x=-1

x=-1/-3

x=1/3

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