5x-(3x-4)+4=14-2(x+1)

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Solution for 5x-(3x-4)+4=14-2(x+1) equation: 



5x-(3x-4)+4=14-2(x+1)

We move all terms to the left:

5x-(3x-4)+4-(14-2(x+1))=0

We get rid of parentheses

5x-3x-(14-2(x+1))+4+4=0



We calculate terms in parentheses: -(14-2(x+1)), so:

14-2(x+1)

determiningTheFunctionDomain
-2(x+1)+14

We multiply parentheses

-2x-2+14

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We add all the numbers together, and all the variables

2x-(-2x+12)+8=0

We get rid of parentheses

2x+2x-12+8=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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