5x-(4x-7)(3x-5)=6-3(4x-9)(x-1

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Solution for 5x-(4x-7)(3x-5)=6-3(4x-9)(x-1 equation: 



5x-(4x-7)(3x-5)=6-3(4x-9)(x-1

We move all terms to the left:

5x-(4x-7)(3x-5)-(6-3(4x-9)(x-1)=0

We multiply parentheses ..

-(+12x^2-20x-21x+35)+5x-(6-3(4x-9)(x-1)=0



We calculate terms in parentheses: -(6-3(4x-9)(x-1), so:

6-3(4x-9)(x-1

determiningTheFunctionDomain
-3(4x-9)(x-1+6

Back to the equation:

-(-3(4x-9)(x-1+6)



We add all the numbers together, and all the variables

-(+12x^2-20x-21x+35)+5x-(-3(4x-9)(x+5)=0

We get rid of parentheses

-12x^2+20x+21x+5x-(-3(4x-9)(x+5)-35=0

We multiply parentheses ..

-12x^2-(-3(+4x^2+20x-9x-45)-35+20x+21x+5x=0

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