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5x-(4x-7)(3x-5)=6-3(4x-9)(x-1)5x-(4x-7)(3x-5)=6-3(4x-9)(x-1)
We move all terms to the left:
5x-(4x-7)(3x-5)-(6-3(4x-9)(x-1)5x-(4x-7)(3x-5))=0
We multiply parentheses ..
-(+12x^2-20x-21x+35)-(6-3(4x-9)(x-1)5x-(+12x^2-20x-21x+35))+5x=0
We calculate terms in parentheses: -(6-3(4x-9)(x-1)5x-(+12x^2-20x-21x+35)), so:
6-3(4x-9)(x-1)5x-(+12x^2-20x-21x+35)
determiningTheFunctionDomain -(+12x^2-20x-21x+35)-3(4x-9)(x-1)5x+6
We get rid of parentheses
-12x^2+20x+21x-3(4x-9)(x-1)5x-35+6
We multiply parentheses ..
-12x^2-3(+4x^2-4x-9x+9)5x+20x+21x-35+6
We add all the numbers together, and all the variables
-12x^2-3(+4x^2-4x-9x+9)5x+41x-29
We multiply parentheses
-12x^2-60x^3+60x^2+135x^2-135x+41x-29
We do not support expression: x^3
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