5x-(6-3x)+6(3x-8)=23x-4(x-5)+6x

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Solution for 5x-(6-3x)+6(3x-8)=23x-4(x-5)+6x equation: 



5x-(6-3x)+6(3x-8)=23x-4(x-5)+6x

We move all terms to the left:

5x-(6-3x)+6(3x-8)-(23x-4(x-5)+6x)=0

We add all the numbers together, and all the variables

5x-(-3x+6)+6(3x-8)-(23x-4(x-5)+6x)=0

We multiply parentheses

5x-(-3x+6)+18x-(23x-4(x-5)+6x)-48=0

We get rid of parentheses

5x+3x+18x-(23x-4(x-5)+6x)-6-48=0



We calculate terms in parentheses: -(23x-4(x-5)+6x), so:

23x-4(x-5)+6x

We add all the numbers together, and all the variables

29x-4(x-5)

We multiply parentheses

29x-4x+20

We add all the numbers together, and all the variables

25x+20

Back to the equation:

-(25x+20)



We add all the numbers together, and all the variables

26x-(25x+20)-54=0

We get rid of parentheses

26x-25x-20-54=0

We add all the numbers together, and all the variables

x-74=0

We move all terms containing x to the left, all other terms to the right

x=74

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