5x-(x+1)=8+2(x-3)

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Solution for 5x-(x+1)=8+2(x-3) equation:



5x-(x+1)=8+2(x-3)
We move all terms to the left:
5x-(x+1)-(8+2(x-3))=0
We get rid of parentheses
5x-x-(8+2(x-3))-1=0
We calculate terms in parentheses: -(8+2(x-3)), so:
8+2(x-3)
determiningTheFunctionDomain 2(x-3)+8
We multiply parentheses
2x-6+8
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
We add all the numbers together, and all the variables
4x-(2x+2)-1=0
We get rid of parentheses
4x-2x-2-1=0
We add all the numbers together, and all the variables
2x-3=0
We move all terms containing x to the left, all other terms to the right
2x=3
x=3/2
x=1+1/2

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