5x-(x+3)=1/3(9x-18)-5

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Solution for 5x-(x+3)=1/3(9x-18)-5 equation: 



5x-(x+3)=1/3(9x-18)-5

We move all terms to the left:

5x-(x+3)-(1/3(9x-18)-5)=0



Domain of the equation: 3(9x-18)-5)!=0

x∈R



We get rid of parentheses

5x-x-(1/3(9x-18)-5)-3=0

We multiply all the terms by the denominator


5x*3(9x-18)-5)-x*3(9x-18)-5)-(1-3*3(9x-18)-5)=0

We add all the numbers together, and all the variables

5x*3(9x-18)-5)-x*3(9x-18)-5)-(1-3*3(9x=0

Wy multiply elements

15x^2(9-5)-x*3(9x-18)-3*3(9x-5)-(1=0

We add all the numbers together, and all the variables

15x^24-x*3(9x-18)-3*3(9x-5)-(1=0

We add all the numbers together, and all the variables

15x^24-x*3(9x-18)-3*3(9x-5)=0

Wy multiply elements

15x^24-3x^2(9-9x(9=0

We do not support expression: x^24

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