5x-(x+3)=1/3(9x=18)-5

Solution for 5x-(x+3)=1/3(9x=18)-5 equation:

5x-(x+3)=1/3(9x=18)-5

We move all terms to the left:

5x-(x+3)-(1/3(9x)=0


Domain of the equation: 39x!=0

x!=0/39

x!=0

x∈R


We get rid of parentheses

5x-x-(1/39x-3=0

We multiply all the terms by the denominator


5x*39x-x*39x-3-3-(1=0

We add all the numbers together, and all the variables

5x*39x-x*39x=0

Wy multiply elements

195x^2-39x^2=0

We add all the numbers together, and all the variables

156x^2=0

a = 156; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·156·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{312}=0$