5x-(x+4)=10-2(x-5)

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Solution for 5x-(x+4)=10-2(x-5) equation: 



5x-(x+4)=10-2(x-5)

We move all terms to the left:

5x-(x+4)-(10-2(x-5))=0

We get rid of parentheses

5x-x-(10-2(x-5))-4=0



We calculate terms in parentheses: -(10-2(x-5)), so:

10-2(x-5)

determiningTheFunctionDomain
-2(x-5)+10

We multiply parentheses

-2x+10+10

We add all the numbers together, and all the variables

-2x+20

Back to the equation:

-(-2x+20)



We add all the numbers together, and all the variables

4x-(-2x+20)-4=0

We get rid of parentheses

4x+2x-20-4=0

We add all the numbers together, and all the variables

6x-24=0

We move all terms containing x to the left, all other terms to the right

6x=24

x=24/6

x=4

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