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5x-(x+8)=5-(2x+1)
We move all terms to the left:
5x-(x+8)-(5-(2x+1))=0
We get rid of parentheses
5x-x-(5-(2x+1))-8=0
We calculate terms in parentheses: -(5-(2x+1)), so:We add all the numbers together, and all the variables
5-(2x+1)
determiningTheFunctionDomain -(2x+1)+5
We get rid of parentheses
-2x-1+5
We add all the numbers together, and all the variables
-2x+4
Back to the equation:
-(-2x+4)
4x-(-2x+4)-8=0
We get rid of parentheses
4x+2x-4-8=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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