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5x-(x-6)=3(x+1)
We move all terms to the left:
5x-(x-6)-(3(x+1))=0
We get rid of parentheses
5x-x-(3(x+1))+6=0
We calculate terms in parentheses: -(3(x+1)), so:We add all the numbers together, and all the variables
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
4x-(3x+3)+6=0
We get rid of parentheses
4x-3x-3+6=0
We add all the numbers together, and all the variables
x+3=0
We move all terms containing x to the left, all other terms to the right
x=-3
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