5x-1(x-2)=2x-4(x-8)

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Solution for 5x-1(x-2)=2x-4(x-8) equation: 



5x-1(x-2)=2x-4(x-8)

We move all terms to the left:

5x-1(x-2)-(2x-4(x-8))=0



We calculate terms in parentheses: -(2x-4(x-8)), so:

2x-4(x-8)

We multiply parentheses

2x-4x+32

We add all the numbers together, and all the variables

-2x+32

Back to the equation:

-(-2x+32)



We get rid of parentheses

5x-1(x-2)+2x-32=0

We add all the numbers together, and all the variables

7x-1(x-2)-32=0

We move all terms containing x to the left, all other terms to the right

7x-1(x-2)=32

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