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5x-1/2(4x+16)=-6(x+1)-2
We move all terms to the left:
5x-1/2(4x+16)-(-6(x+1)-2)=0
Domain of the equation: 2(4x+16)!=0We multiply all the terms by the denominator
x∈R
5x*2(4x+16)-((-6(x+1)-2))*2(4x+16)-1=0
We calculate terms in parentheses: -((-6(x+1)-2))*2(4x+16), so:Wy multiply elements
(-6(x+1)-2))*2(4x+16
10x^2(4-((-6(x+1)-2))*2(4x+16)-1=0
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