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5x-12=-2+5x(x-2)
We move all terms to the left:
5x-12-(-2+5x(x-2))=0
We calculate terms in parentheses: -(-2+5x(x-2)), so:We get rid of parentheses
-2+5x(x-2)
determiningTheFunctionDomain 5x(x-2)-2
We multiply parentheses
5x^2-10x-2
Back to the equation:
-(5x^2-10x-2)
-5x^2+5x+10x+2-12=0
We add all the numbers together, and all the variables
-5x^2+15x-10=0
a = -5; b = 15; c = -10;
Δ = b2-4ac
Δ = 152-4·(-5)·(-10)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5}{2*-5}=\frac{-20}{-10} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5}{2*-5}=\frac{-10}{-10} =1 $
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