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5x-14=x(24+4x)
We move all terms to the left:
5x-14-(x(24+4x))=0
We add all the numbers together, and all the variables
5x-(x(4x+24))-14=0
We calculate terms in parentheses: -(x(4x+24)), so:We get rid of parentheses
x(4x+24)
We multiply parentheses
4x^2+24x
Back to the equation:
-(4x^2+24x)
-4x^2+5x-24x-14=0
We add all the numbers together, and all the variables
-4x^2-19x-14=0
a = -4; b = -19; c = -14;
Δ = b2-4ac
Δ = -192-4·(-4)·(-14)
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{137}}{2*-4}=\frac{19-\sqrt{137}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{137}}{2*-4}=\frac{19+\sqrt{137}}{-8} $
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