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5x-16x^2=4x=34
We move all terms to the left:
5x-16x^2-(4x)=0
We add all the numbers together, and all the variables
-16x^2+x=0
a = -16; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-16)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-16}=\frac{-2}{-32} =1/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-16}=\frac{0}{-32} =0 $
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