5x-2(2-3x)=(x-3)-20

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Solution for 5x-2(2-3x)=(x-3)-20 equation: 



5x-2(2-3x)=(x-3)-20

We move all terms to the left:

5x-2(2-3x)-((x-3)-20)=0

We add all the numbers together, and all the variables

5x-2(-3x+2)-((x-3)-20)=0

We multiply parentheses

5x+6x-((x-3)-20)-4=0



We calculate terms in parentheses: -((x-3)-20), so:

(x-3)-20

We get rid of parentheses

x-3-20

We add all the numbers together, and all the variables

x-23

Back to the equation:

-(x-23)



We add all the numbers together, and all the variables

11x-(x-23)-4=0

We get rid of parentheses

11x-x+23-4=0

We add all the numbers together, and all the variables

10x+19=0

We move all terms containing x to the left, all other terms to the right

10x=-19

x=-19/10

x=-1+9/10

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