5x-2(2-3x)=4(x-3)-20

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Solution for 5x-2(2-3x)=4(x-3)-20 equation: 



5x-2(2-3x)=4(x-3)-20

We move all terms to the left:

5x-2(2-3x)-(4(x-3)-20)=0

We add all the numbers together, and all the variables

5x-2(-3x+2)-(4(x-3)-20)=0

We multiply parentheses

5x+6x-(4(x-3)-20)-4=0



We calculate terms in parentheses: -(4(x-3)-20), so:

4(x-3)-20

We multiply parentheses

4x-12-20

We add all the numbers together, and all the variables

4x-32

Back to the equation:

-(4x-32)



We add all the numbers together, and all the variables

11x-(4x-32)-4=0

We get rid of parentheses

11x-4x+32-4=0

We add all the numbers together, and all the variables

7x+28=0

We move all terms containing x to the left, all other terms to the right

7x=-28

x=-28/7

x=-4

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