5x-2(2-3x)=4(x-4)-23

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Solution for 5x-2(2-3x)=4(x-4)-23 equation: 



5x-2(2-3x)=4(x-4)-23

We move all terms to the left:

5x-2(2-3x)-(4(x-4)-23)=0

We add all the numbers together, and all the variables

5x-2(-3x+2)-(4(x-4)-23)=0

We multiply parentheses

5x+6x-(4(x-4)-23)-4=0



We calculate terms in parentheses: -(4(x-4)-23), so:

4(x-4)-23

We multiply parentheses

4x-16-23

We add all the numbers together, and all the variables

4x-39

Back to the equation:

-(4x-39)



We add all the numbers together, and all the variables

11x-(4x-39)-4=0

We get rid of parentheses

11x-4x+39-4=0

We add all the numbers together, and all the variables

7x+35=0

We move all terms containing x to the left, all other terms to the right

7x=-35

x=-35/7

x=-5

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