5x-2(2x)+1=3(x-4)

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Solution for 5x-2(2x)+1=3(x-4) equation: 



5x-2(2x)+1=3(x-4)

We move all terms to the left:

5x-2(2x)+1-(3(x-4))=0

We add all the numbers together, and all the variables

-17x-(3(x-4))+1=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

-17x-3x+12+1=0

We add all the numbers together, and all the variables

-20x+13=0

We move all terms containing x to the left, all other terms to the right

-20x=-13

x=-13/-20

x=13/20

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