5x-2(2x+1)=3(x-4)

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Solution for 5x-2(2x+1)=3(x-4) equation: 



5x-2(2x+1)=3(x-4)

We move all terms to the left:

5x-2(2x+1)-(3(x-4))=0

We multiply parentheses

5x-4x-(3(x-4))-2=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

x-(3x-12)-2=0

We get rid of parentheses

x-3x+12-2=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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