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5x-2(2x-1)=2(3x-4)
We move all terms to the left:
5x-2(2x-1)-(2(3x-4))=0
We multiply parentheses
5x-4x-(2(3x-4))+2=0
We calculate terms in parentheses: -(2(3x-4)), so:We add all the numbers together, and all the variables
2(3x-4)
We multiply parentheses
6x-8
Back to the equation:
-(6x-8)
x-(6x-8)+2=0
We get rid of parentheses
x-6x+8+2=0
We add all the numbers together, and all the variables
-5x+10=0
We move all terms containing x to the left, all other terms to the right
-5x=-10
x=-10/-5
x=+2
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