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5x-2(3-2x)=3(x-3)-9
We move all terms to the left:
5x-2(3-2x)-(3(x-3)-9)=0
We add all the numbers together, and all the variables
5x-2(-2x+3)-(3(x-3)-9)=0
We multiply parentheses
5x+4x-(3(x-3)-9)-6=0
We calculate terms in parentheses: -(3(x-3)-9), so:We add all the numbers together, and all the variables
3(x-3)-9
We multiply parentheses
3x-9-9
We add all the numbers together, and all the variables
3x-18
Back to the equation:
-(3x-18)
9x-(3x-18)-6=0
We get rid of parentheses
9x-3x+18-6=0
We add all the numbers together, and all the variables
6x+12=0
We move all terms containing x to the left, all other terms to the right
6x=-12
x=-12/6
x=-2
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