5x-2(3-4x)=3(x-4)-24

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Solution for 5x-2(3-4x)=3(x-4)-24 equation: 



5x-2(3-4x)=3(x-4)-24

We move all terms to the left:

5x-2(3-4x)-(3(x-4)-24)=0

We add all the numbers together, and all the variables

5x-2(-4x+3)-(3(x-4)-24)=0

We multiply parentheses

5x+8x-(3(x-4)-24)-6=0



We calculate terms in parentheses: -(3(x-4)-24), so:

3(x-4)-24

We multiply parentheses

3x-12-24

We add all the numbers together, and all the variables

3x-36

Back to the equation:

-(3x-36)



We add all the numbers together, and all the variables

13x-(3x-36)-6=0

We get rid of parentheses

13x-3x+36-6=0

We add all the numbers together, and all the variables

10x+30=0

We move all terms containing x to the left, all other terms to the right

10x=-30

x=-30/10

x=-3

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